Optimal. Leaf size=199 \[ \frac {b c \log (F) \sin ^3(d+e x) F^{c (a+b x)}}{b^2 c^2 \log ^2(F)+9 e^2}-\frac {3 e \sin ^2(d+e x) \cos (d+e x) F^{c (a+b x)}}{b^2 c^2 \log ^2(F)+9 e^2}+\frac {6 b c e^2 \log (F) \sin (d+e x) F^{c (a+b x)}}{b^4 c^4 \log ^4(F)+10 b^2 c^2 e^2 \log ^2(F)+9 e^4}-\frac {6 e^3 \cos (d+e x) F^{c (a+b x)}}{b^4 c^4 \log ^4(F)+10 b^2 c^2 e^2 \log ^2(F)+9 e^4} \]
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Rubi [A] time = 0.07, antiderivative size = 199, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {4434, 4432} \[ \frac {b c \log (F) \sin ^3(d+e x) F^{c (a+b x)}}{b^2 c^2 \log ^2(F)+9 e^2}+\frac {6 b c e^2 \log (F) \sin (d+e x) F^{c (a+b x)}}{10 b^2 c^2 e^2 \log ^2(F)+b^4 c^4 \log ^4(F)+9 e^4}-\frac {6 e^3 \cos (d+e x) F^{c (a+b x)}}{10 b^2 c^2 e^2 \log ^2(F)+b^4 c^4 \log ^4(F)+9 e^4}-\frac {3 e \sin ^2(d+e x) \cos (d+e x) F^{c (a+b x)}}{b^2 c^2 \log ^2(F)+9 e^2} \]
Antiderivative was successfully verified.
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Rule 4432
Rule 4434
Rubi steps
\begin {align*} \int F^{c (a+b x)} \sin ^3(d+e x) \, dx &=-\frac {3 e F^{c (a+b x)} \cos (d+e x) \sin ^2(d+e x)}{9 e^2+b^2 c^2 \log ^2(F)}+\frac {b c F^{c (a+b x)} \log (F) \sin ^3(d+e x)}{9 e^2+b^2 c^2 \log ^2(F)}+\frac {\left (6 e^2\right ) \int F^{c (a+b x)} \sin (d+e x) \, dx}{9 e^2+b^2 c^2 \log ^2(F)}\\ &=-\frac {6 e^3 F^{c (a+b x)} \cos (d+e x)}{9 e^4+10 b^2 c^2 e^2 \log ^2(F)+b^4 c^4 \log ^4(F)}+\frac {6 b c e^2 F^{c (a+b x)} \log (F) \sin (d+e x)}{9 e^4+10 b^2 c^2 e^2 \log ^2(F)+b^4 c^4 \log ^4(F)}-\frac {3 e F^{c (a+b x)} \cos (d+e x) \sin ^2(d+e x)}{9 e^2+b^2 c^2 \log ^2(F)}+\frac {b c F^{c (a+b x)} \log (F) \sin ^3(d+e x)}{9 e^2+b^2 c^2 \log ^2(F)}\\ \end {align*}
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Mathematica [A] time = 0.70, size = 154, normalized size = 0.77 \[ \frac {F^{c (a+b x)} \left (3 \cos (3 (d+e x)) \left (b^2 c^2 e \log ^2(F)+e^3\right )-3 e \cos (d+e x) \left (b^2 c^2 \log ^2(F)+9 e^2\right )-2 b c \log (F) \sin (d+e x) \left (\cos (2 (d+e x)) \left (b^2 c^2 \log ^2(F)+e^2\right )-b^2 c^2 \log ^2(F)-13 e^2\right )\right )}{4 \left (b^4 c^4 \log ^4(F)+10 b^2 c^2 e^2 \log ^2(F)+9 e^4\right )} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.62, size = 171, normalized size = 0.86 \[ \frac {{\left (3 \, e^{3} \cos \left (e x + d\right )^{3} - 9 \, e^{3} \cos \left (e x + d\right ) + 3 \, {\left (b^{2} c^{2} e \cos \left (e x + d\right )^{3} - b^{2} c^{2} e \cos \left (e x + d\right )\right )} \log \relax (F)^{2} - {\left ({\left (b^{3} c^{3} \cos \left (e x + d\right )^{2} - b^{3} c^{3}\right )} \log \relax (F)^{3} + {\left (b c e^{2} \cos \left (e x + d\right )^{2} - 7 \, b c e^{2}\right )} \log \relax (F)\right )} \sin \left (e x + d\right )\right )} F^{b c x + a c}}{b^{4} c^{4} \log \relax (F)^{4} + 10 \, b^{2} c^{2} e^{2} \log \relax (F)^{2} + 9 \, e^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [C] time = 0.28, size = 1311, normalized size = 6.59 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.44, size = 336, normalized size = 1.69 \[ -\frac {3 F^{a c} e \,{\mathrm e}^{b c x \ln \relax (F )}}{4 \left (1+\tan ^{2}\left (\frac {d}{2}+\frac {e x}{2}\right )\right ) \left (e^{2}+b^{2} c^{2} \ln \relax (F )^{2}\right )}+\frac {3 F^{a c} e \,{\mathrm e}^{b c x \ln \relax (F )} \left (\tan ^{2}\left (\frac {d}{2}+\frac {e x}{2}\right )\right )}{4 \left (1+\tan ^{2}\left (\frac {d}{2}+\frac {e x}{2}\right )\right ) \left (e^{2}+b^{2} c^{2} \ln \relax (F )^{2}\right )}+\frac {3 F^{a c} b c \ln \relax (F ) {\mathrm e}^{b c x \ln \relax (F )} \tan \left (\frac {d}{2}+\frac {e x}{2}\right )}{2 \left (1+\tan ^{2}\left (\frac {d}{2}+\frac {e x}{2}\right )\right ) \left (e^{2}+b^{2} c^{2} \ln \relax (F )^{2}\right )}+\frac {3 F^{a c} e \,{\mathrm e}^{b c x \ln \relax (F )}}{4 \left (1+\tan ^{2}\left (\frac {3 e x}{2}+\frac {3 d}{2}\right )\right ) \left (9 e^{2}+b^{2} c^{2} \ln \relax (F )^{2}\right )}-\frac {3 F^{a c} e \,{\mathrm e}^{b c x \ln \relax (F )} \left (\tan ^{2}\left (\frac {3 e x}{2}+\frac {3 d}{2}\right )\right )}{4 \left (1+\tan ^{2}\left (\frac {3 e x}{2}+\frac {3 d}{2}\right )\right ) \left (9 e^{2}+b^{2} c^{2} \ln \relax (F )^{2}\right )}-\frac {F^{a c} \ln \relax (F ) b c \,{\mathrm e}^{b c x \ln \relax (F )} \tan \left (\frac {3 e x}{2}+\frac {3 d}{2}\right )}{2 \left (1+\tan ^{2}\left (\frac {3 e x}{2}+\frac {3 d}{2}\right )\right ) \left (9 e^{2}+b^{2} c^{2} \ln \relax (F )^{2}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.49, size = 813, normalized size = 4.09 \[ -\frac {{\left (F^{a c} b^{3} c^{3} \log \relax (F)^{3} \sin \left (3 \, d\right ) - 3 \, F^{a c} b^{2} c^{2} e \cos \left (3 \, d\right ) \log \relax (F)^{2} + F^{a c} b c e^{2} \log \relax (F) \sin \left (3 \, d\right ) - 3 \, F^{a c} e^{3} \cos \left (3 \, d\right )\right )} F^{b c x} \cos \left (3 \, e x\right ) - {\left (F^{a c} b^{3} c^{3} \log \relax (F)^{3} \sin \left (3 \, d\right ) + 3 \, F^{a c} b^{2} c^{2} e \cos \left (3 \, d\right ) \log \relax (F)^{2} + F^{a c} b c e^{2} \log \relax (F) \sin \left (3 \, d\right ) + 3 \, F^{a c} e^{3} \cos \left (3 \, d\right )\right )} F^{b c x} \cos \left (3 \, e x + 6 \, d\right ) + 3 \, {\left (F^{a c} b^{3} c^{3} \log \relax (F)^{3} \sin \left (3 \, d\right ) + F^{a c} b^{2} c^{2} e \cos \left (3 \, d\right ) \log \relax (F)^{2} + 9 \, F^{a c} b c e^{2} \log \relax (F) \sin \left (3 \, d\right ) + 9 \, F^{a c} e^{3} \cos \left (3 \, d\right )\right )} F^{b c x} \cos \left (e x + 4 \, d\right ) - 3 \, {\left (F^{a c} b^{3} c^{3} \log \relax (F)^{3} \sin \left (3 \, d\right ) - F^{a c} b^{2} c^{2} e \cos \left (3 \, d\right ) \log \relax (F)^{2} + 9 \, F^{a c} b c e^{2} \log \relax (F) \sin \left (3 \, d\right ) - 9 \, F^{a c} e^{3} \cos \left (3 \, d\right )\right )} F^{b c x} \cos \left (e x - 2 \, d\right ) + {\left (F^{a c} b^{3} c^{3} \cos \left (3 \, d\right ) \log \relax (F)^{3} + 3 \, F^{a c} b^{2} c^{2} e \log \relax (F)^{2} \sin \left (3 \, d\right ) + F^{a c} b c e^{2} \cos \left (3 \, d\right ) \log \relax (F) + 3 \, F^{a c} e^{3} \sin \left (3 \, d\right )\right )} F^{b c x} \sin \left (3 \, e x\right ) + {\left (F^{a c} b^{3} c^{3} \cos \left (3 \, d\right ) \log \relax (F)^{3} - 3 \, F^{a c} b^{2} c^{2} e \log \relax (F)^{2} \sin \left (3 \, d\right ) + F^{a c} b c e^{2} \cos \left (3 \, d\right ) \log \relax (F) - 3 \, F^{a c} e^{3} \sin \left (3 \, d\right )\right )} F^{b c x} \sin \left (3 \, e x + 6 \, d\right ) - 3 \, {\left (F^{a c} b^{3} c^{3} \cos \left (3 \, d\right ) \log \relax (F)^{3} - F^{a c} b^{2} c^{2} e \log \relax (F)^{2} \sin \left (3 \, d\right ) + 9 \, F^{a c} b c e^{2} \cos \left (3 \, d\right ) \log \relax (F) - 9 \, F^{a c} e^{3} \sin \left (3 \, d\right )\right )} F^{b c x} \sin \left (e x + 4 \, d\right ) - 3 \, {\left (F^{a c} b^{3} c^{3} \cos \left (3 \, d\right ) \log \relax (F)^{3} + F^{a c} b^{2} c^{2} e \log \relax (F)^{2} \sin \left (3 \, d\right ) + 9 \, F^{a c} b c e^{2} \cos \left (3 \, d\right ) \log \relax (F) + 9 \, F^{a c} e^{3} \sin \left (3 \, d\right )\right )} F^{b c x} \sin \left (e x - 2 \, d\right )}{8 \, {\left (b^{4} c^{4} \cos \left (3 \, d\right )^{2} \log \relax (F)^{4} + b^{4} c^{4} \log \relax (F)^{4} \sin \left (3 \, d\right )^{2} + 9 \, {\left (\cos \left (3 \, d\right )^{2} + \sin \left (3 \, d\right )^{2}\right )} e^{4} + 10 \, {\left (b^{2} c^{2} \cos \left (3 \, d\right )^{2} \log \relax (F)^{2} + b^{2} c^{2} \log \relax (F)^{2} \sin \left (3 \, d\right )^{2}\right )} e^{2}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.22, size = 190, normalized size = 0.95 \[ -\frac {3\,F^{c\,\left (a+b\,x\right )}\,\left (\cos \left (e\,x\right )-\sin \left (e\,x\right )\,1{}\mathrm {i}\right )\,\left (\cos \relax (d)-\sin \relax (d)\,1{}\mathrm {i}\right )}{8\,\left (e+b\,c\,\ln \relax (F)\,1{}\mathrm {i}\right )}+\frac {F^{c\,\left (a+b\,x\right )}\,\left (\cos \left (3\,e\,x\right )+\sin \left (3\,e\,x\right )\,1{}\mathrm {i}\right )\,\left (\cos \left (3\,d\right )+\sin \left (3\,d\right )\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{8\,\left (b\,c\,\ln \relax (F)+e\,3{}\mathrm {i}\right )}+\frac {F^{c\,\left (a+b\,x\right )}\,\left (\cos \left (3\,e\,x\right )-\sin \left (3\,e\,x\right )\,1{}\mathrm {i}\right )\,\left (\cos \left (3\,d\right )-\sin \left (3\,d\right )\,1{}\mathrm {i}\right )}{8\,\left (3\,e+b\,c\,\ln \relax (F)\,1{}\mathrm {i}\right )}-\frac {F^{c\,\left (a+b\,x\right )}\,\left (\cos \left (e\,x\right )+\sin \left (e\,x\right )\,1{}\mathrm {i}\right )\,\left (\cos \relax (d)+\sin \relax (d)\,1{}\mathrm {i}\right )\,3{}\mathrm {i}}{8\,\left (b\,c\,\ln \relax (F)+e\,1{}\mathrm {i}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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